program to merged Array

94./*Write a program to merged Array*/

#include<stdio.h>

#include<conio.h>

#include<process.h>

main()

{

int array1[100],array2[100],array3[200];

int i,j,k;

int m,n,p;

clrscr();

printf("How many elements you want in first array:");

scanf("%d",&m);

if(m>100)

{

printf("Array out of bound, press any key to exit...");

getch();

exit(1);

}

printf("Enter %d elements in the first array:\n",m);

for(i=0;i<m;i++)

{

scanf("%d",&array1[i]);

}

printf("How many elements you want is second array:");

scanf("%d",&n);

if(n>100)

{

printf("Array out of bound,press any key to exit...");

getch();

exit(1);

}

printf("\nEnter %d elements for the second array:\n",n);

for(i=0;i<n;i++)

{

scanf("%d",&array2[i]);

}

for(i=0;i<m;i++)

{

array3[i]=array1[i];

}

for(j=m,k=0;k<n;k++,j++)

{

array3[j]=array2[k];

}

p=m+n;

printf("The merged array is\n");

for(i=0;i<p;i++)

{

printf("array3[%d]=%d\n",i,array3[i]);

}

getch();

 }

OUTPUT

            How many elements you want in first array : 4

            Enter 4 elements in the first array

            1

            3

            5

            7

            How many elements you want is second array : 4

            Enter 4 elements for the second array

            1

            2

            4

            6

            The merged array is

            array3[0] = 1

            array3[0] = 3

            array3[0] = 5

            array3[0] = 7

            array3[0] = 1

            array3[0] = 2

            array3[0] = 4

            array3[0] = 6